Comments for Lettergram http://lettergram.org Imagining is the hard part. Sat, 24 Mar 2012 05:06:41 +0000 hourly 1 http://wordpress.org/?v=3.3.2 Comment on I am Man by Lettergram http://lettergram.org/to-the-living/#comment-219 Lettergram Sat, 24 Mar 2012 05:06:41 +0000 http://lettergram.org/?p=351#comment-219 Hoping this one finally wins me a competition, I doubt it, but hey the last one that beat me in a competition didn't even rhyme... so who knows! Hoping this one finally wins me a competition, I doubt it, but hey the last one that beat me in a competition didn’t even rhyme… so who knows!

]]> Comment on I am Man by Zach http://lettergram.org/to-the-living/#comment-217 Zach Thu, 22 Mar 2012 17:56:39 +0000 http://lettergram.org/?p=351#comment-217 nice! nice!

]]> Comment on Programming Problem by Zach http://lettergram.org/338/#comment-211 Zach Wed, 07 Mar 2012 03:14:27 +0000 http://lettergram.org/?p=338#comment-211 Same here. The more we point out each other's tiny mistakes the more precise we can become. Same here. The more we point out each other’s tiny mistakes the more precise we can become.

]]> Comment on Programming Problem by Lettergram http://lettergram.org/338/#comment-210 Lettergram Wed, 07 Mar 2012 01:58:27 +0000 http://lettergram.org/?p=338#comment-210 I edited it to read what I stated because there was a possibility of receiving an error with some compilers. Which thank you for pointing out, I NEED TO BECOME BETTER! I edited it to read what I stated because there was a possibility of receiving an error with some compilers. Which thank you for pointing out, I NEED TO BECOME BETTER!

]]> Comment on Programming Problem by Zach http://lettergram.org/338/#comment-209 Zach Wed, 07 Mar 2012 01:39:56 +0000 http://lettergram.org/?p=338#comment-209 #include int main() { int kwh, cust, i; kwh = cust = -1; if ((kwh && cust) != -1) printf("golly, zach's pretentious explanation is accurate.\n"); else printf("zach is retarded. QED.\n"); } How I was interpreting it originally. #include

int main() {
int kwh, cust, i;
kwh = cust = -1;

if ((kwh && cust) != -1)
printf(“golly, zach’s pretentious explanation is accurate.\n”);
else
printf(“zach is retarded. QED.\n”);
}

How I was interpreting it originally.

]]> Comment on Programming Problem by Zach http://lettergram.org/338/#comment-208 Zach Wed, 07 Mar 2012 01:38:54 +0000 http://lettergram.org/?p=338#comment-208 Aha! I just realized something. In the original statement: while(kwh && cust != -1) The '!=' takes precedence over the &&. So if the user did enter -1 -1, it would compare -1 && (-1 != -1), ultimately failing the test; breaking out of the loop. I totally overlooked this. Aha! I just realized something. In the original statement:

while(kwh && cust != -1)

The ‘!=’ takes precedence over the &&. So if the user did enter -1 -1, it would compare -1 && (-1 != -1), ultimately failing the test; breaking out of the loop. I totally overlooked this.

]]> Comment on Programming Problem by Zach http://lettergram.org/338/#comment-207 Zach Wed, 07 Mar 2012 01:10:06 +0000 http://lettergram.org/?p=338#comment-207 You're right Robb, but you're also a dick. Responding pretentiously to something pretentious leaves us no where. I wasn't trying to be. Although I could have left the QED out, I was just trying to be helpful. You’re right Robb, but you’re also a dick. Responding pretentiously to something pretentious leaves us no where. I wasn’t trying to be. Although I could have left the QED out, I was just trying to be helpful.

]]> Comment on Programming Problem by robb http://lettergram.org/338/#comment-206 robb Wed, 07 Mar 2012 00:33:20 +0000 http://lettergram.org/?p=338#comment-206 https://gist.github.com/1990107 https://gist.github.com/1990107

]]> Comment on Programming Problem by Lettergram http://lettergram.org/338/#comment-205 Lettergram Wed, 07 Mar 2012 00:29:04 +0000 http://lettergram.org/?p=338#comment-205 I agree with what you are saying for the most part, however, in the requirements (which you can't see because I didn't copy them...) it was a requisite to have to type >> -1 -1 to end the program (WHY? I have no idea). However, with the program I have above is ran, if you type -1 -1 it will end the program, granted it should probably read: while(kwh != -1 && cust != -1){ instead of what I have entered. I agree with what you are saying for the most part, however, in the requirements (which you can’t see because I didn’t copy them…) it was a requisite to have to type >> -1 -1 to end the program (WHY? I have no idea). However, with the program I have above is ran, if you type -1 -1 it will end the program, granted it should probably read:

while(kwh != -1 && cust != -1){

instead of what I have entered.

]]> Comment on Programming Problem by Zach http://lettergram.org/338/#comment-204 Zach Tue, 06 Mar 2012 23:43:02 +0000 http://lettergram.org/?p=338#comment-204 Just for cleaning purposes, check your main method. It requires the user to enter -1 followed by -1 (instead of what was probably assumed: entering a single -1). An alternate main method could be: int main(void){ /* Input Values */ int kwh; /* kilowatt-hours per customer */ int cust; /* customer number */ char STOP[2] = ""; while(1){ printf("Enter customer number and KWH: "); scanf("%d %d", &cust, &kwh); charge_calc_kwh(&kwh, &cust); totaling(&kwh, &cost); printf("Would you like to enter another data entry?('n' or 'y') "); scanf("%s", &STOP[0]); if (STOP[0] == 'n'){ break;} } More verbose, but it seems to make more sense. Your check: """ while(kwh && cust != -1){ """ could never happen; this is because if the user did want to end the program and typed: >>> -1 -1 (-1 && -1) would result in a 1 (or a 0 if one of their entries was '0'), and never a -1 like in your check. The '&&' is a logical AND, and interprets the entries as either a 0 or a 1. QED Just for cleaning purposes, check your main method. It requires the user to enter -1 followed by -1 (instead of what was probably assumed: entering a single -1). An alternate main method could be:

int main(void){
/* Input Values */
int kwh; /* kilowatt-hours per customer */
int cust; /* customer number */
char STOP[2] = “”;
while(1){
printf(“Enter customer number and KWH: “);
scanf(“%d %d”, &cust, &kwh);
charge_calc_kwh(&kwh, &cust);
totaling(&kwh, &cost);
printf(“Would you like to enter another data entry?(‘n’ or ‘y’) “);
scanf(“%s”, &STOP[0]);
if (STOP[0] == ‘n’){
break;}
}

More verbose, but it seems to make more sense. Your check:

“”" while(kwh && cust != -1){ “”"

could never happen; this is because if the user did want to end the program and typed:

>>> -1 -1

(-1 && -1) would result in a 1 (or a 0 if one of their entries was ’0′), and never a -1 like in your check. The ‘&&’ is a logical AND, and interprets the entries as either a 0 or a 1.

QED

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